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When you run the re-order point report you get a requisition for each part that needs to be ordered in order to replenish stock levels. If the supplier is the same for those parts is there any methodto create just one purchase requisition or RFQ and send it to the supplier instead of creating multiple requisitions?
Best answer by ShawnBerk
View originalThe parts are analyzed individually against the Planning Data settings for the part which is irrespective of the primary supplier, so the need to have a requisition and the process of creating the requisition are two separate steps. The parts are not accumulated and held such that only one requisition is created per supplier. Due dates and a few other parameters can also have an effect. If all of the parts are going to be due on the same day or within a few days, you will get some grouped in that fashion on a single requisition. As that is not often the case, it requires a user to intervene and decide the best approach. The grouping by supplier is what the Planner and/or Buyer do with the requisitions to decide if they can be processed together. If so, highlighting all requisitions to be combined and selecting requisition to order will convert all requisitions to the same PO if that is the desire.
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Hi Shawn,
Thank you for the information.
As you have stated, is there a specific process/flow to follow in order to get a single requisition of parts which are going to be due on the same day/within few days?
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The parts are analyzed individually against the Planning Data settings for the part which is irrespective of the primary supplier, so the need to have a requisition and the process of creating the requisition are two separate steps. The parts are not accumulated and held such that only one requisition is created per supplier. Due dates and a few other parameters can also have an effect. If all of the parts are going to be due on the same day or within a few days, you will get some grouped in that fashion on a single requisition. As that is not often the case, it requires a user to intervene and decide the best approach. The grouping by supplier is what the Planner and/or Buyer do with the requisitions to decide if they can be processed together. If so, highlighting all requisitions to be combined and selecting requisition to order will convert all requisitions to the same PO if that is the desire.
Hi
Thank you for the information.
As you have stated, is there a specific process/flow to follow in order to get a single requisition of parts which are going to be due on the same day/within few days?
My reply seems to have not been saved. With order point, the emergence of the requisitions is going to be random really based on the consumption rate and the lead times of the parts. There is no way to force the grouping through the Order Proposal process or by any particular setup. Simply setup the purchase requisition lines overview to be ordered by supplier number and wanted date, then pick the items by date that need to be on the same PO. That is as much grouping as there is. There are no control parameters to set a date window or anything else that will force the grouping on a single requisition, you can only group the requisitions on a single order if that is the desired outcome.
In Inventory Part → Planning Data → you can find the planning attributes for the part. Method G combined with a proper Order Cover Time would lead to the behavior you expect.
Below is an excerpt from IFS Docs regarding planning methods:
If an order must be placed, the lot size is determined by the total demand during the order cover time, which is specified in days in the inventory part register. The order cover time can be complemented with minimum, maximum, and multiple lot sizes.
| Day | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 |
| Demand | 8 | 27 | 30 | 40 | 25 | 40 | 25 | 30 | 0 | 50 | |
| Calculated Balance | 10 | 2 | 95 | 65 | 25 | 0 | 55 | 30 | 0 | 0 | 0 |
| Order Proposal | 0 | 120 | 0 | 0 | 0 | 95 | 0 | 0 | 0 | 50 |
Example: The order cover time for the part is 4 days. On the second day, the estimated quantity on hand is 2, making the demand 27 - 2 = 25. MRP totals the demand, 25, with the demand of the four following days. The calculations for this period are:
| Day 2: | 25 + 30 + 40 + 25 = 120 | The lot size is 120. |
| Day 6: | 40+ 25 + 30 + 0= 95 | The lot size is 95. |
| Day 10: | 0+ 50 = 50 | The lot size is 50. |
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My reply seems to have not been saved. With order point, the emergence of the requisitions is going to be random really based on the consumption rate and the lead times of the parts. There is no way to force the grouping through the Order Proposal process or by any particular setup. Simply setup the purchase requisition lines overview to be ordered by supplier number and wanted date, then pick the items by date that need to be on the same PO. That is as much grouping as there is. There are no control parameters to set a date window or anything else that will force the grouping on a single requisition, you can only group the requisitions on a single order if that is the desired outcome.
+4
In Inventory Part → Planning Data → you can find the planning attributes for the part. Method G combined with a proper Order Cover Time would lead to the behavior you expect.
Below is an excerpt from IFS Docs regarding planning methods:
If an order must be placed, the lot size is determined by the total demand during the order cover time, which is specified in days in the inventory part register. The order cover time can be complemented with minimum, maximum, and multiple lot sizes.
| Day | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 |
| Demand | 8 | 27 | 30 | 40 | 25 | 40 | 25 | 30 | 0 | 50 | |
| Calculated Balance | 10 | 2 | 95 | 65 | 25 | 0 | 55 | 30 | 0 | 0 | 0 |
| Order Proposal | 0 | 120 | 0 | 0 | 0 | 95 | 0 | 0 | 0 | 50 |
Example: The order cover time for the part is 4 days. On the second day, the estimated quantity on hand is 2, making the demand 27 - 2 = 25. MRP totals the demand, 25, with the demand of the four following days. The calculations for this period are:
| Day 2: | 25 + 30 + 40 + 25 = 120 | The lot size is 120. |
| Day 6: | 40+ 25 + 30 + 0= 95 | The lot size is 95. |
| Day 10: | 0+ 50 = 50 | The lot size is 50. |
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